Solution



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m = 222 g = 0.222 kg
c = 4200
= (39 + 273) - (19 + 273) = 20 K
E = 0.222 4200 20 = 18,648 J

This means that 18.648 kJ of heat is released when 2 g of sulphur is burned.
1 mole sulphur = 32 g

Therefore the burning of 32 g releases
= 298.4 kJ

The reaction is exothermic.
Therefore heat of combustion = -298.4 kJ